std::chrono::year::is_leap
来自cppreference.com
constexpr bool is_leap() const noexcept; |
(C++20 起) | |
确定 *this 是否表示外推格里高利历中的闰年。
若存储的年份值满足下列条件则 *this 表示闰年
- 被 4 整除且不被 100 整除;或
- 被 400 整除。
返回值
若 *this
表示闰年则为 true ,否则为 false 。
示例
运行此代码
#include <iostream> #include <chrono> int main() { using namespace std::chrono_literals; for (const std::chrono::year y : {2020y, 2021y, 2000y, 3000y}) { if (const int iy{ static_cast<int>(y) }; y.is_leap()) { std::cout << iy << " is a leap year because it is divisible by " << (iy % 400 == 0 ? "400\n" : "4 and not divisible by 100\n"); } else { std::cout << iy << " is not a leap year\n"; } } }
输出:
2020 is a leap year because it is divisible by 4 and not divisible by 100 2021 is not a leap year 2000 is a leap year because it is divisible by 400 3000 is not a leap year